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15k^2+15k=200
We move all terms to the left:
15k^2+15k-(200)=0
a = 15; b = 15; c = -200;
Δ = b2-4ac
Δ = 152-4·15·(-200)
Δ = 12225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12225}=\sqrt{25*489}=\sqrt{25}*\sqrt{489}=5\sqrt{489}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{489}}{2*15}=\frac{-15-5\sqrt{489}}{30} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{489}}{2*15}=\frac{-15+5\sqrt{489}}{30} $
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